Question

write the nth term of an. A.P 1/m,1+m/m,1+2m/n

Answer 1

Answer: (1+mn-m)/m

Step-by-step explanation: Please find in the attachment...

Hope it helps!!!

Answer 2

Answer:

$n^{th}\:term \: of\:a.p=a_{n}=\frac{1+mn-m}{m}$

Step-by-step explanation:

$Given\: A.P\:\\\frac{1}{m},\frac{1+m}{m},\frac{1+2m}{m}$

$common \: difference (d)\\=a_{2}-a_{1}\\=\frac{1+m}{m}-\frac{1}{m}\\=\frac{1+m-1}{m}\\=\frac{m}{m}\\=1$

\* We know that,

$\boxed {n^{th}\: term =a_{n}=a+(n-1)d}$

$\implies a_{n}=\frac{1}{m}+(n-1)1\\=\frac{1+(n-1)m}{m}\\=\frac{1+mn-m}{m}$

Therefore,

$n^{th}\:term =a_{n}=\frac{1+mn-m}{m}$