Write the nth term of an A.P. the sum of whose n terms is Sn.
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Answer:
sn=n/2[2a+(n-1)d] is the answer of this question
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an = a + (n-1) d
Sn = n / 2 (2a + (n - 1) d)
Step-by-step explanation:
(i) An arithmetic progression with first term a and common difference d, will have its Nth term as:
an = a + (n-1) d
Sum of n terms = n / 2 (2a + (n - 1) d)
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