write the nuber of zeroes in the end of a number whose prime factorization is 2*2×5*3×3*2×17
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Step-by-step explanation:
i think the answer might be 4 zeros
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we have,
2² × 5³ × 3² × 17
2² × 5² × 5 × 3² × 17
(2 × 5)² × 5 × 3² × 17
(10)² × 5 × 3² × 17
100 × 5 × 3² × 17
Clearly, there are two zeros at the end of the given number.
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