Question

Write the number 79 as the difference of the squares of two consecutive natural numbers and find the numbers.

Answer 1

Answer:

Step-by-step explanation:

Let one no. be x

And other be x + 1

A. T. Q.

( x + 1 )^2 -( x )^2 = 79

Using (a+b)^2 = a^2 + b^2 + 2ab

x^2 + 1 +2x - x^2 = 79

2x + 1 = 79

2x = 79 - 1

2x = 78

x = 78/2

x = 39

Thus one no. is 39 and other is (x + 1) which is 40

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Answer 2

Let one no. be x

And other be x + 1

A. T. Q.

( x + 1 )^2 -( x )^2 = 79

Using (a+b)^2 = a^2 + b^2 + 2ab

x^2 + 1 +2x - x^2 = 79

2x + 1 = 79

2x = 79 - 1

2x = 78

x = 78/2

x = 39

Thus one no. is 39 and other is (x + 1) which is 40