Question

write the number designation of a group that has 2 electrons beyond a Noble gas configuration. Please don't copy it from google and give Mr correct answer it is from 11 class

Answer 1

$\huge \mathfrak{Answer:-}$

The number designation of a group that has $\bold{2\:electrons}$ beyond a Noble gas configuration will be $2.$

It will belong to $\bold{Group\:2}$ in the $\bold{Periodic\:Table.}$

$\huge {Be\:Brainly}$❤️

Answer 2

Designation of a group means here you have to write the electronic configuration of elements which have 2 electrons left after  the nobel gas electronic configuration. So if we look that Group 2 elements like Beryllium (Be at. no=4) have electronic configuration as 1s2 2s2 and other element as Magnesium (Mg at. no=12) have electronic configuration as 1s2 2s2 2p6 3s2 and after Mg we have Calcium (Cl at. no=20) with electronic configuration as 1s2 2s2 2p6 3s2 3p6 4s2 and so on.

Now moving on the configuration of Nobel gases firstly we have Helium (He at. no=2) electronic configuration as 1s2 then we have Neon (Ne at. no=10) with electronic configuration as 1s2 2s2 2p6 and so on. Now moving on the electronic configuration of Be and He

Be= 1s2 2s2

He=1s2

In configuration of Be we can write like this [He]2s2 and after Helium we have 2 electrons i.e. 2s2, similarly configuration of Mg can be written as [Ne] 3s2 after Neon we are left with only with 2 electrons that are 3s2.

Summary- Writing the electronic configuration of elements in such a way that the element's configuration contains nobel gas configuration and after the nobel gas configuration there are electrons left as per question. You can check this que- no of designation of a group that has 1 electrons beyond a Nobel gas configuration.