write the number in the end of a number whose prime factorization is 2^2 × 5^3 × 3^2 × 17.
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Answered by
94
2²×5³×3²×17
=4×125×9×17
=76500
number of zeroes = 2
lakshaykr:
but how
Answered by
39
Answer:
2 zeroes
Step-by-step explanation:
To find the number of zeroes at the end of the number formed we first need to find the number.
Performing the operations we have :
2² × 3² × 5³ × 17 = 76500
The number formed by the product of the prime factors above is 76500.
We can now count the number of zeroes at the end of this number.
The number of zeroes at the end of this number are two.
So there are 2 zeroes.
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