Question

write the number of atoms each in following in the following molecules 1st Na2Co3 2nd H2So4​

Answer 1

Answer:

Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water

5.3 g + 6 g → 8.2 g + 2.2 g + 0.9 g

LHS RHS

11.3 g = 11.3 g

(Mass of reactant) (Mass of product)

This shows, that during a chemical reaction mass of reactact = mass of product.

Answer 2

Answer:

Na2Co3= 6 atoms

H2So4= 7 atoms

Explanation:

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