Question

write the number of digit in the cube root of 1728​

Answer 1

Answer:

2 digits

Step-by-step explanation:

∛1728 = 12, which has 2 digits.

Answer 2

Step-by-step explanation:

We have to find the cube root of 1728 :

$\sqrt[3]{1728}$

Now if we solve it (I am solving in Factorisation Method, the picture of solving is given above)

Now, we get the factors : 2×2×2×2×2×2×3×3×3...

Now to find the cube, we have to form triplets with the factor, like :

There are three ‘2’s so we will count three ‘2’s as one ‘2’

Similarly, if we form Triplets, we will get :

[ Two ‘2’ and One ‘3’ ]

Therefore we have to multiply the Triplets :

$2 \times 2 \times 3$

$= \: 4 \times 3$

$= 12$

Therefore the cube root of 1728 is – 12

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