Question

Write the number of digits when 200^8 is written in base 10 form.

Answer 1

Step-by-step explanation:

he characteristic of the logarithm of a positive number is positive and it is one less than the number of digits in the number.

Take logarithm of the given number:-

=log(2^100)

=100*log(2)

=100*0.301

=30.1

hence total number of digits:-

=30+1

31

Answer 2

Answer:

The answer 19

Step-by-step explanation:

$200^8=(200)^8=(2\times 10^2)^8\\=2^8\times (10^2)^8=256\times 10^{16}$

Thus number of digits is $3+16=19$