Write the number of protons present in the atom of the given element
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Atomic number = Number of protons
Hence , number of protons in K atoms = 19
Number of neutrons = Mass number - Atomic number
Hence , number of neutrons in K atom = 39−19=20
Number of electrons = Number of protons
Hence , the number of electrons = 19
And electronic configuration of K atom = 2,8,8,1
Since K atom has 4 shells , hence it belongs to fourth period.
With one valence electron , it belongs to group 1
Number of protons in P atom = 15
Number of neutrons in P atom = 31−15=16
Number of electrons in P atom = 15
And electronic configuration of P atom = 2,8,5
Since it has three shells , it belong to period 3 and with 5 valence electrons Phosphorous is found in five plus ten that is 15
th
group
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