Math, asked by mohit87, 1 year ago

write the number of real root of the equations x^2+31x1+2=0

Answers

Answered by Neetubhardwaj

number of real roots are 2

Answered by TPS

discriminant = b^2 - 4ac = 31^2 - 4×1×2 =953 > 0

Since discriminant is greater than 0, it has two real roots.

TPS: If the equation is x^2 + 31x + 2 = 0

TPS: it has 2 real roots

Neetubhardwaj: yes TPS is ryt

mohit87: the question is x^2+31x1+2=0

TPS: 31x1 doesnt mean anything. 31 x^1 means 31x

mohit87: ok

TPS: Otherwise if you take 31x1 to be 31 × 1, then it wont have any real solution

TPS: but that is very unlikely.

TPS: Go with 2 real roots. That will be correct.

TPS: And thanks for marking brainliest:)

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