write the number of solution of the following pair of linear equation x+2y-8=0, 2x+4y=16
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x+2y=8
And 2x+4y=16
These given equations are in the form:
a
1
x+b
1
y+c
1
=0 and
a
2
x+b
2
y+c
2
=0
Where
a
1
=1,b
1
=2 and c
1
=8
a
2
=2,b
2
=4 and c
2
=16
a
2
a
1
=
2
1
,
b
2
b
1
=
4
2
=
2
1
System has infinitely many solutions
Answered by
3
Answer:
This pair of equation will have infinitely many solutions.
Step-by-step explanation:
This pair of equation will have infinitely many solutions.
Because 2x + 4y = 16 can be written as x + 2y = 8 or x + 2y - 8 = 0.
So, both these equations are actually same.
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