Write the number of ways 7 men and 7 women can sit on round table such that no two women sit together
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Note that if we think as independent chain of women and independent chain on men as the fixing position of men we will get 7!X7! But as we know that a position will also included where it both the chain will revert themselves.
For example
TUVWXYZ and UVWXYZT
ABCDEFG and BCDEFGA are equal so the answer will be 7!X6!
For example
TUVWXYZ and UVWXYZT
ABCDEFG and BCDEFGA are equal so the answer will be 7!X6!
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If we see that no two women can sit together it means that women should ait in between two men and for which the number of men are (7-1)! which is 6! and women are 7! ways and the answer is 6!×7!
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