Write the number of zeroes 4x³ - x⁴ + 3x + 5
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Number of zeroes 4x³ - x⁴ + 3x + 5 is 4
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Step-by-step explanation:
How do I factor out (x⁴-4x³+5x²-4x+4) ^¼/ (x²-3x+2) ^½ ? What is the factor of that?
x^4 -4x^3 +5x^2 -4x+4
two is a zero here so x-2 is a factor
Let poly be
(x-2) ( x^3 +ax^2+bx-2 )
Coeff of x = -2-2b = -4
b = 1
Coeff of x^3 = a-2 = -4 , a= -2
x^3 -2x^2 +x-2 = 0
Again 2 is a zero so x-2 is a root
x-2) (x^2+ax +1)
Coeff of x = 1–2a = 1
a = 0
So our original polynomial becomes
x-2)^2 (x^2+1) / x-1 ) ( x-2)
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