CBSE BOARD X, asked by aman4945, 1 year ago

write the number of zeroes in the end of a number who's prime factorization is 2^2×5^3×3^2×17

Answers

Answered by CanadianGirl
0

isnt this a board question CBSE ????


aman4945: phn no bej de pura question paper baj duga
Answered by innocent01
2

hello my dear mate!!!

your answer is here....

Given,

2^2*5^3*3^2*17

prime factorization is :

2×2×5×5×5×3×3×17 = 76500

It has 2 zeroes in its end.

it may help you...:))

Similar questions