Math, asked by mariyamridha04, 10 months ago

write the number of zeroes in the end of a number whose prime factorization is 2square*5cube*3square*17

Answers

Answered by anamaydubey952
1

Answer

Only 2 zeros.

As when we multiply all of this given prime factors given in the question we get the no.

Step-by-step explanation:

2*2=4

5*5*5=125

3*3=9

17*1=17

therefore multiply all of this no. we get

4*125*9*17=76,500

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