Question

write the number of zeros in the end of a number whose prime factorization is 2 ^ 2 × 5 ^ 3 × 3 ^ 2 × 17​

Answer 1

2×2×5×5×5×3×3×17= 76500

i.e. it has 2 zeros in its end.

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Answer 2

we have,

2² × 5³ × 3² × 17

2² × 5² × 5 × 3² × 17

(2 × 5)² × 5 × 3² × 17

(10)² × 5 × 3² × 17

Clearly, there are two zeros at the end of the given number.