Write the number of zeros in the end of a prime number whose prime factorization is 2 square into 5 into 3 square into 17
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Answer:
Step-by-step explanation:
he given expression, = 2² x 5³ x 3² x 17
we know that zeroes in an expression are a result of number of 10's in it. The only way to make a 10 is the product of 2 and 5. Hence the number of zeroes in an expression will be the number of 2 or 5 whichever is minimum.
2² x 5³ x 3² x 17
= 2x2 x 5x5x5 x 3² x 17
= (2x5) x (2x5) x 5 x 3² x 17
= 10 x 10 x 5 x 3² x 17
Hence from the expression we can see that there will be 2 zeroes in the given expression.
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we have,
2² × 5³ × 3² × 17
2² × 5² × 5 × 3² × 17
(2 × 5)² × 5 × 3² × 17
(10)² × 5 × 3² × 17
Clearly, there are two zeros at the end of the given number.
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