Math, asked by Hush411, 10 months ago

Write the number of zeros in the end of a prime number whose prime factorization is 2 square into 5 into 3 square into 17

Answers

Answered by ahmadzohra157
0

Answer:

Step-by-step explanation:

he given expression,  = 2² x 5³ x 3² x 17

we know that zeroes in an expression are a result of number of 10's in it. The only way to make a 10 is the product of 2 and 5. Hence the number of zeroes in an expression will be the number of 2 or 5 whichever is minimum.

2² x 5³ x 3² x 17

= 2x2 x 5x5x5 x 3² x 17

= (2x5) x (2x5) x 5 x 3² x 17

= 10 x 10 x 5 x 3² x 17

Hence from the expression we can see that there will be 2 zeroes in the given expression.

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Answered by ChromaticSoul
2

we have,

2² × 5³ × 3² × 17

2² × 5² × 5 × 3² × 17

(2 × 5)² × 5 × 3² × 17

(10)² × 5 × 3² × 17

Clearly, there are two zeros at the end of the given number.

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