Math, asked by annapurana21, 10 months ago

write the number of zeros of the polynomial p(x)= x³+2x²+x+6​

Answers

Answered by vc500720
2

Step-by-step explanation:

Answer: p(X)=x³+2x²+x+6. p (-1)=(-1)³+2*(-1)²+(-1)+6. = -1+2+(-1)+6. = 2-2 +6. =6. so, p(x) is not zero of polynomial. 3.0.

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