Chemistry, asked by DhanvanthriRock, 6 months ago

write the obond order of N2 O2 and H2​

Answers

Answered by Anonymous
1

Answer:

here is the answer

Explanation:

Bond order= No of Bonds between the compound

Bond orders are calculate using Molecular orbital theory,which is quite time consuming and confusing. Just remember the method I  Give you :)

10=1

11=1.5

12=2

13=2.5

14=3               ⇔       Just remember this,all other reduce by 0.5

15=2.5

16=2

17=1.5

18=1

Now what are all these numbers?

LHS is the number of electrons in the atom or compound

RHS = bond order.

Now lets get back to the question:

N₂=N+N = 7e⁻+7e⁻ = 14e-  which has bond order =3 ,from the above data

O₂=8e⁻+8e⁻ = 16e⁻  which has bond order = 2

O₂⁺=8e⁻+8e⁻ - 1e⁻ = 15e⁻ which has bond order= 2.5

O₂⁻ = 8e⁻ +8e⁻ +1e⁻ =17 e⁻ which has bond order=1.5

This method is for easily getting answer.

The formal ways is by filling the no of electron in the MOT table given below,and using the formula

No of Bond order= (No of bonding electrons- No of anti bonding electrons)/2

You get the same result. :)

Answered by Anonymous
0

Answer:

bond order of n2 is n2 hahaaha h2 is h2

Explanation:

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