Write the of atoms in 23 g of sodium atom. (a) 54g of aluminum
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Answer:23g Na=6.022 X 10^23 atoms
54g Al= 12.05 X 10^23 atoms.
Explanation: one mole of any element = Avogadro number of atoms
Therefore 23g of Na= 1 mole of Na
23g of Na= 6.022 X 10^23 atoms of Na
54g of Al= 54 X 6.022 X 10^23/26.98
= 12.05 X 10^23 atoms of Al.
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