Write the order and angle of rotational symmetry of equilateral triangle. with the help of figure
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Order 3
Equilateral triangle/Rotational symmetry
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Therefore the component of force along the x-axis is
Fx=Fcos(360−θ)=Fcos(360–300)=Fcos(60)
( ∵cos is positive in forth quadrent)
⇒Fx=300×12=150N
The component of force along the x-axis is
Fy=Fsin(360−θ)=Fsin(360–300)=F(−sin(60))
[ sin(360−θ)=−sinθ this is because (360−θ) lies in the forth quadrent where sin is negative according to ASTC rule.]
Fy=300×(−0.866)=−259.8N
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