Question

write the other two numbers of the Pythagorean triplet whose one number is 36

Answer 1

Answer:

(36,323,325)

Step-by-step explanation:

A pythagoran triplet can be written in the base form (2n, n²-1 , n²+1) where n≥2 and n∈Z

Let us check if 36 can equal any of the values.

i) 2n = 36

n = 18

We have confirmed one possibility.

ii) n² - 1 = 36

n² = 37

n = √37

√37 is irrational so this is not a possibiity.

iii) n² + 1 = 36

n² = 35

n = √35

Once again this is irrational so this is also not a possibility.

We must take n=18

(2n, n²-1 , n²+1)

= ( 2*18, 324 - 1, 324 +1)

= (36,323,325)

Hope this helps.

Answer 2

Step-by-step explanation:

$\tt \: To \: find \: this \: we \: use \: formula \\ \\ \longrightarrow \: \boxed{2m, \: {m}^{2} +1 , {m}^{2} - 1} \\ \\ \tt \longrightarrow \: 2m =3 6 \\ \longrightarrow \tt \: m = 18 \\ \\ \longrightarrow \: \tt {m}^{2} + 1 \\ \tt \longrightarrow \: {(18)}^{2} + 1 \: = 324 + 1 = 325 \\ \\ \longrightarrow \: \tt {m}^{2} - 1 \\ \\ \longrightarrow \ \tt \: ( {18)}^{2} - 1 = 324 - 1 = 323 \\ \\ \tt \: Other \: Two: \: 325 \: and \: 323$