Question

Write the oxidation and reducing half reactions of the equation Zn+2HCl = ZnCl2+H2

Answer 1

Explanation:

Zn + 2 HCl H2 + ZnCl2 Zinc's oxidation number changes from 0 to +2; it is oxidized.

Zn Zn2+ + 2 e- Hydrogen's oxidation number changes from +1 to 0; it is reduced. ...

2 H+ + 2 e- H2 Both half-reactions use two electrons; therefore, they can be added as is to give:

Answer 2

Explanation:

Oxidation is the loss of electrons or the addition of oxygen; reduction is the gain of electrons or the addition of hydrogen. Zn → Zn 2+ +2e − (oxidation); C 2H 4 + H 2 → C 2H 6 (reduction) (answers will vary)