Question

Write the Oxidation and Reduction half-reaction.
a) Zn + Cu2+ ⇒Zn2+ + Cu
b) Cu + 2Ag+ ⇒ Cu2+ + 2Ag
c) 2Al + 3Ni2+ ⇒ 2Al3+ + 2Ni


Please answer correctly

Answer 1

Hey !

Here is your answer. Go through it •‿•

a) • Oxidation: Loss of electrons

(consider oxidation of Fe to Fe3+ as in Fe2O3 , rust)

• Reduction: Gain of electrons

(Reduction of formal charge)

Conclusion — Zn(s) + Cu2+ → Zn2+ + Cu(s)

b) Consider each process indivually:

Oxidation Cu (s) → Cu2+ (aq) + 2 e-

Reduction [Ag+ + e- → Ag (s) ] x 2

Overall: Cu (s) + 2Ag(aq) → Cu2(aq) + 2Ag (s)

c) Oxidation and Reduction - Chemical reactions that involve a transfer of electrons.

Conclusion — 2Al (s) + 3Ni2+ (aq) → 2Al3+ (aq) +

3Ni (s).

And if you are satisfied with my answer then please don't forget to mark it as brainliest ◉‿◉