Question

Write the oxidation and reduction involve- Fe+s=fes H2+cl2=2hcl Zn+cu2=zn2+cut Cu+i2=cui2

Answer 1

Fe + S ------> FeS

oxidation : Fe → Fe⁺²

reduction: S → S²⁻

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H₂ + Cl₂ ------> 2 HCl

oxidation: H → H⁺

reduction: Cl → Cl⁻

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Zn + Cu⁺² --------> Zn⁺² + Cu

oxidation: Zn → Zn⁺²

reduction: Cu⁺² → Cu

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Cu + I₂ ---------> CuI₂

oxidation: Cu → Cu⁺²

reduction: I → I⁻

Hope it helps