Question

write the oxidation state and co-valency of aluminum in [AIF6]^3-​

Answer 1

Answer:

Oxidation state is + 3 and covalency is 6.

The entire radical must have a -3 charge.

Thus x + 6 x (-1) = -3.

There are a total of 6 F which donate electrons for 1 Al.

So covalency is 6.

Answer 2

Answer:

heafjdjg, khfkh gjxyicljxougixuf