Question

write the pair of indegese whose
product is -36
and whose difference is is 15​

Answer 1

Answer:

12, -3

Step-by-step explanation:

12*-3 = -36

12-(-3) = 15

Answer 2

Answer:

the required integers are 12 &-3

Step-by-step explanation:

Let the pair of required integers be m and n

their product = m×n =-36

their difference = m-n = 15 .......(1)

we know that (a+b)^2= (a-b)^2+4ab

(m+n)^2=(15)^2+4(-36)

=>(m+n)^2=225-144

=>(m+n)^2=81

=>(m+n)=√81

=>m+n = 9..........(2)

solving (1) and (2)

m+n+m-n=15+9

2m=24

m=12.....(3)

now, n =-3

therefore m =12 & n = -3

check:

product=12×-3=-36

difference= 12- (-3)=12+3=15