Question

write the pair of integers whose product is -36 and difference is 15​

Answer 1

Answer:

answer for the given problem is given

Answer 2

AnswEr:-

There are two pairs possible:-

1. -2 And 13.
2. -13 And 2.

ExplanaTion:-

Here we have to write the pair of integers whose product is -36 and difference is 15.

So,

Let the integers be x and y.

Therefore ATQ:-

$\\ \tt\mapsto x - y = 15. \\ \\ \tt\mapsto x= 15 + y. ... \: eq(1).$

And,

$\\ \tt\mapsto x \times y = - 36. \\ \\ \tt\mapsto (15 + y) \times y = - 36. \\ \\ \tt\mapsto {y}^{2} + 15y + 36 = 0. \\ \\ \tt\mapsto {y}^{2} + (1 3+ 2)y + 36 = 0. \\ \\ \rm(by \: \: splitting \: \: middle \: \: term). \\ \\ \tt\mapsto {y}^{2} + 13y + 2y + 36 = 0. \\ \\ \tt\mapsto y(y + 13) + 2(y + 13) = 0. \\ \\ \tt\mapsto (y + 2)(y + 13) = 0. \\ \\ \tt\mapsto y = - 2 \: \: \: \: or \: \: \: \: y - 13.$

By putting the bothe vakue ofby in eq(1) we get:-

$\tt\leadsto x = 15 + y. \\ \\ \tt\leadsto x = 15 + ( - 2). \\ \\ \tt\leadsto x = 15 - 2. \\ \\ \tt\leadsto x = 13. \\ \\ \rm and \: \: also \\ \\ \tt\leadsto x = 15 + y. \\ \\ \tt\leadsto x = 15 + ( - 13). \\ \\ \tt\leadsto x = 15 - 13. \\ \\ \tt\leadsto x = 2.$

So there are two such pairs of integers are possible:-

1) -2 And 13.

2) -13 And 2.

So the pair of integers are -2 and 13 and also -13 And 2.