Question

Write the phthagorean triplet whose one member is 18

Answer 1

Answer:

hey!

2m= 18

m= 18/2

m= 9

m^2-1

= 9^2 -1

= 80

m^2+1

=> 9^2 +1

=> 82

hope it will be helpful ✌️

Answer 2

Answer:

Step-by-step explanation:

the Pythagorean triplet is mostly of the form 2n, $n^{2}$+1, $n^{2}$-1

so lets take

18 = 2n

n = 9

therefore, the other two members of the Pythagorean triplet are

$n^{2}$+1 = 81 + 1 = 82

$n^{2}$-1 = 81 - 1 = 80

we can check also as

6724 = 82^2 = 324 + 6400 = 18^2 + 80^2

CHEERS MATE

PLEASE MARK BRAINLIEST.