write the phythagorean triplet if one number is 14
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Pythagorean triplets are of the form 2m,m²-1 and m²+1
Given one number,that is 14
14 can not be in the form of m²-1 or m²+1 as we get the following result.
m²-1=14
m²=13;m=√13
m²+1=14
m²=15;m=√15
So,it is of the form 2m
2m=14
m=7
So,the other Pythagorean triplets are of the form m²-1 and m²+1
m²-1=7²-1
=49-1=48
m²+1=7²+1
=49+1=50
So,the three Pythagorean triplets are 14,48 and 50.
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Given one number,that is 14
14 can not be in the form of m²-1 or m²+1 as we get the following result.
m²-1=14
m²=13;m=√13
m²+1=14
m²=15;m=√15
So,it is of the form 2m
2m=14
m=7
So,the other Pythagorean triplets are of the form m²-1 and m²+1
m²-1=7²-1
=49-1=48
m²+1=7²+1
=49+1=50
So,the three Pythagorean triplets are 14,48 and 50.
.
.
.
________
HOPE THIS HELPS
FOLLOW FOR MORE
#KHUSHI #UR HELPING HAND
(≧▽≦)
Answered by
3
2m = 14
m = 14÷2
m = 7
(m)^2 -1
(7)^2 -1
49 -1
48
(m)^2 + 1
(7)^2 +1
49 + 1
50
triplet of 14 is
7 , 48 ,50
m = 14÷2
m = 7
(m)^2 -1
(7)^2 -1
49 -1
48
(m)^2 + 1
(7)^2 +1
49 + 1
50
triplet of 14 is
7 , 48 ,50
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