Question

Write the point of discontinuity of f(x)=[x] on the interval (-3,3)

Answer 1

f(x)=[x

3

−3]

f(x)=[x

3

]−3

Integral part function is discontinuous at integral points

x∈(1,2)

⇒x

3

∈(1,8)

So x

3

becomes 2,3,4,5,6,7 in (1,2)

So the function is discontinuous at 6 points

Option C is correct.