Question

Write the point where the graph of the linear equation 2x + 3y = 6 cuts the y-axis​

Answer 1

Answer:

the point where the line 2x + 3y = 6 cuts y-axis is (0,2).

Step-by-step explanation:

Let the point where 2x + 3y = 6 cuts y axis be (0,y).

Then, the given equation will satisfy the point (0,y).

Putting the value of x = 0.

2x + 3y = 6

2*0 + 3y =6

3y = 6

y = 6/3

y = 2

Therefore, the point where the line 2x + 3y = 6 cuts y-axis is (0,2).