Write the polynomial, if its zeros are -9/2 and -3/2 respectively
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hey mate
Given-- ą(alpha)=-9/2
ß(bita)= -3/2
ąß(product of zeroes)= -9/2×-3/2
= 27/4
ą+ß(sum of zeroes)= -9/2+(-3/2)
= -12/2
K(x²+(sum of zeroes)x + (product of zeroes)
K(x²+27x/4 - 12/2)
hope it'll help you ....✌
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