Question

write the polynomial p(x)=2x^2 -7x-15as a product of two first degree polynomial?
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Answer 1

Answer:

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Answer 2

Answer:

      p(x) = 2x^2 - 7x - 15

      p(x) = 2x^2 - 7x - 15 = 0

[ for writing the polynomial p(x) = 2x^2 - 7x - 15 as the product of two first degree polynomials , we need to find the value of x first ]

Step-by-step explanation ;

  x = -b +  $\sqrt b^2 -4ac / 2a$                      

  a = 2

  b = -7

  c = -15

  x = -b + $\sqrt b^2 - 4ac / 2a$

     = - (-7) + $\sqrt (-7)^2 - 4$ x 2 x (-15) / 2 x 2

     = 7 + $\sqrt 49 - (-120) / 4$

     = 7 + $\sqrt 49 + 120 / 4$

     = 7 + $\sqrt{ 169$ / 4

     = 7 + 13 / 4

x = 7 + 13 / 4      or     x = 7 - 13 / 4

   = 20 / 4                      = - 6 / 4

   =  5                             = - 3 / 2

therefore ; x = 5 or  (-3/2)

p (5) = 0                               p (-3/2) = 0

x = (-5) is a factor                x = (2x + 3) is a factor

answer :

p(x) = 2x^2 - 7x - 15  = (x-5) (2x+3)