Question

write the polynomial the product and sum of whose zeros are negative 9 by 2 and 3 by 2​

Answer 1

Answer:

let the the zeros be

$\alpha \: \: and \: \: \: \: \: \beta$

and ...

Step-by-step explanation:

as product of zeros=

as sum of zeros =

$\alpha + \beta = \frac{ - b}{a}$

so

$\frac{ - 9}{2} = \frac{ - b}{a}$

so a= 2 and b= 9.

now product of zeros

$\alpha \beta = \frac{c}{a}$

$\frac{3}{2} = \frac{c}{a}$

that is. c= 3...

SO OUR POLINOMIAL WOULD BE....

${2x}^{2} + 9x + 3$

hope it helps ; )