Write the polynomial whose two zeroes are -2-root2 and 2-root3
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Step-by-step explanation:
zeroes are (-2 - √2) and (2 - √3)
sum of zeroes = (-2 - √2) + (2 - √3)
= - 2 - √2 + 2 - √3
= -√2 - √3
= -(√2 + √3)
product of zeroes = (-2 - √2)(2 - √3)
- 4 + 2√3 - 2√2 + √6
polynomial = x² - (sum of zeroes)x + product of zeroes = 0
x² -[-(√2 + √3]x + (-4 + 2√3 - 2√2 + √6) = 0
x² + (√2 + √3)x + (-4 + 2√3 - 2√2 + √6) = 0
Answered by
1
Step-by-step explanation:
Hope this answer will help and sorry for bad handwriting.
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