Math, asked by vishnurajD, 1 year ago

write the polynomial whose zeroes are - 2 and - 1/3.

Answers

Answered by Anonymous
12
Heya!!!

Here's your answer friend,

The given zeroes of a polynomial are -2 and -1/3

i.e. (x +2) and (x + 1/3)

(x+2)(x+1/3)

x² + x/3 + 2x + 2/3

x² + 7x/3 + 2/3

Multiplying the whole equation by 3 we get,

3x² + 7x + 2
is the required polynomial

Hope it helps you : )
Answered by FallingLeaf213
1

Answer:

3x²+7x+2

Step-by-step explanation:

Let,

a = -2, B = -1/3

a+B = (-2) + (-1/3)

= -2 - 1/3

= -6 - 1/3

= -7/3

aB = (-2) (-1/3)

= 2/3

Polynomial Form = x² - (-7/3)x + (2/3)

= x² + 7/3x +2/3

Multiplying By 3,

= 3x² + 3 * 7/3x + 3 * 2/3

= 3x² + 7x + 2

★ 3x² + 7x + 2 is the required polynomial.

HOPE THIS HELPS...

Similar questions