write the polynomial whose zeroes are - 2 and - 1/3.
Answers
Answered by
12
Heya!!!
Here's your answer friend,
The given zeroes of a polynomial are -2 and -1/3
i.e. (x +2) and (x + 1/3)
(x+2)(x+1/3)
x² + x/3 + 2x + 2/3
x² + 7x/3 + 2/3
Multiplying the whole equation by 3 we get,
3x² + 7x + 2
is the required polynomial
Hope it helps you : )
Here's your answer friend,
The given zeroes of a polynomial are -2 and -1/3
i.e. (x +2) and (x + 1/3)
(x+2)(x+1/3)
x² + x/3 + 2x + 2/3
x² + 7x/3 + 2/3
Multiplying the whole equation by 3 we get,
3x² + 7x + 2
is the required polynomial
Hope it helps you : )
Answered by
1
Answer:
3x²+7x+2
Step-by-step explanation:
Let,
a = -2, B = -1/3
a+B = (-2) + (-1/3)
= -2 - 1/3
= -6 - 1/3
= -7/3
aB = (-2) (-1/3)
= 2/3
Polynomial Form = x² - (-7/3)x + (2/3)
= x² + 7/3x +2/3
Multiplying By 3,
= 3x² + 3 * 7/3x + 3 * 2/3
= 3x² + 7x + 2
★ 3x² + 7x + 2 is the required polynomial.
HOPE THIS HELPS...
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