Math, asked by HackerLOL, 1 year ago

write the polynomial whose zeroes are
2 -  \sqrt{3 \: } and \: 2 +  \sqrt{3}

Answers

Answered by ishwarsinghdhaliwal
4

Sum \:  of  \: zeroes  \:  (\alpha  +  \beta )=  \:  2  -  \sqrt{3}  + 2  +  \sqrt{3}  = 4 \\ Product \: of \: zeroes \: ( \alpha  \beta ) = (2 -  \sqrt{3} )(2 +  \sqrt{3} ) =  {2}^{2}  -  ({   \sqrt{3} })^{2}  = 4 - 3 = 1 \\  \\  {x}^{2}  - ( \alpha  +  \beta )x +  (\alpha  \beta ) \\  {x}^{2}  - 4x + 1
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