Question

write the polynomial whose zeros are -2 and -1by3

Answer 1

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Answer 2

Given, alpha= (-2) and beeta = -1/3

Since, Quadratic polynomial =
k[ x2- (sum of zeroes)× x +(product of zeroes) ]

=) k[x2-( -2+ (-1/3) ) ×x + (-2 ×-1/3 ) ]=0

=) k [x2 -(-7/3)x + 2/3]=0

=)k [x2 +7x/3 +2/3]=0
=) k[3x2+7x+2 whole divided by 3] =0

=)k[3x2+7x+2] =0


Hence, 3x2+7x+2 is the required quadratic polynomial.

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