write the polynomial whose zeros are -2 and -1by3
Answers
Answered by
21
Hope this helps you ☺☺
Attachments:
Answered by
15
Given, alpha= (-2) and beeta = -1/3
Since, Quadratic polynomial =
k[ x2- (sum of zeroes)× x +(product of zeroes) ]
=) k[x2-( -2+ (-1/3) ) ×x + (-2 ×-1/3 ) ]=0
=) k [x2 -(-7/3)x + 2/3]=0
=)k [x2 +7x/3 +2/3]=0
=) k[3x2+7x+2 whole divided by 3] =0
=)k[3x2+7x+2] =0
Hence, 3x2+7x+2 is the required quadratic polynomial.
Hope it Helps..
Mark as Brainliest plzz
Since, Quadratic polynomial =
k[ x2- (sum of zeroes)× x +(product of zeroes) ]
=) k[x2-( -2+ (-1/3) ) ×x + (-2 ×-1/3 ) ]=0
=) k [x2 -(-7/3)x + 2/3]=0
=)k [x2 +7x/3 +2/3]=0
=) k[3x2+7x+2 whole divided by 3] =0
=)k[3x2+7x+2] =0
Hence, 3x2+7x+2 is the required quadratic polynomial.
Hope it Helps..
Mark as Brainliest plzz
Similar questions