Question

write the polynomial with zero -2,1,4 and hence find the sum of its zeroes​

Answer 1

Answer:

x³-3x³-6x+8

Step-by-step explanation:

Sum of zeros = -2+1+4 = 3

polynomial format : x³+(b/a)x²+(c/a)x+(d/a)

sum of roots = -b/a = 3

Product of roots = -d/a = -8

sum of product of two roots alternate = c/a = (-2)(1)+(1)(4)+(4)(-2) = -2+4-8 = -6

hence the polynomial is x³-3x²-6x+8