Question

write the polynomial with zero -2 and 3​

Answer 1

Step-by-step explanation:

Q.E = x^2-(a+b)x+ab

=x^2-(-2)x+3

=x^2+2x+3

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Answer 2

Answer:

Step-by-step explanation:

$\alpha =-2 \\\beta = 3\\\\ P(x) = k[x^2+(\alpha +\beta)x+\alpha\beta ]\\P(x) = k[x^2+(-2+3)x+-2*3]\\P(x) = k[x^2+x-6]\\Therefore, P(x) = x^2+x-6 \\where\\ k = 1$

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