Math, asked by kashikbatta123351, 11 months ago

write the polynomials the product and sum of whose zeroes are -9/2 and-3/2respectively.​

Answers

Answered by legend1289
2

Step-by-step explanation:

The product of the polynomials = -²/9

The sum of zeroes = -³/2

The polynomial so required :

K[x²-(sum of zeroes)x+product of Zeroes]

\begin{lgathered}k({x}^{2} + \frac{3}{2} x - \frac{2}{9} ) \\ \\ k( \frac{18 {x}^{2} + 27x - 4}{18} ) \\\end{lgathered}

k(x

2

+

2

3

x−

9

2

)

k(

18

18x

2

+27x−4

)

Where k = 18

So the required polynomial is 18x²+27x-4.

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