Write the preparation of isopropyl chloride using HCl.
Answers
You can prepare directly isopropyl chloride directly using the hydrochloric acid.
When you use a cooled mixture of concentrated HCl, zinc chloride and isopropyl alcohol of 30g you can get the isopropyl chloride.
During the process, isopropyl chloride gets distilled and will be available inside the condenser.
Obtained isopropyl chloride is insoluble in water, and it is a colorless liquid.
Answer:
HCl + propane → propylchloride
Explanation:
Order of reactivity for chlorination
1° : 2° : 3° = 1 : 2.8 : 5
No. of 1° hydrogen in propane = 6
No. of 2° hydrogen in propane = 2
Multiply by reactivity to get percentage
1×6 = 6 & 2.8×2 = 5.6
{6/(6+5.6)}×100 ≈ 52
So here we observe 1° chloride is formed 52% and 2° (reqd. product) is only 48%.
Our main goal of obtaining isopropyl is still not attained. I want to know how