Question

write the principal value of tan^-1(root 3) + sin^-1 (1/5) - cot^-1 (-root 3) +cos ^-1 (1/5)​

Answer 1

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Answer 2

Step-by-step explanation:

tan−13−cot(−3)

∵tan3π=3  and  cot(π−6π)=−3

tan−13=3π

and

cot−1(−3)=π−6π

tan−13−cot(−3) =3π−(π−6π)

=3π−π+6π=−2π