write the principal value of tan^-1(root 3) + sin^-1 (1/5) - cot^-1 (-root 3) +cos ^-1 (1/5)
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Answer:
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Step-by-step explanation:
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Answered by
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Answer:
Solution
tan
−1
(tanx)=x;x∈(
2
−π
,
2
π
)cot
−1
(cotx)=x;x∈(0,π)
tan
−1
(
3
)−cot
−1
(−
3
)
=tan
−1
(tan
3
π
)−cot
−1
(−cot
6
π
)
=tan
−1
(tan
3
π
)−cot
−1
(cot(π−
6
π
))
=tan
−1
(tan
3
π
)−cot
−1
(cot(
6
5π
))
=
3
π
−
6
5π
=
6
−3π
=
2
−π
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