Question

write the principal value of tan-1[sin(-π/2)]​

Answer 1

Answer:

tan−1(sin(2−π)).=tan−1(−sin(2π))=tan−1(−1)=−4π

Answer 2

tan^-1[sin(-π/2)] = tan^-1[-1] = -tan^-1(tan π/4) = -π/4