Chemistry, asked by girishjyotibordoloi, 3 months ago

write the process of synthesis of borazine .​

Answers

Answered by angel163853
0

Explanation:

Borazine can be synthesized by treating diborane and ammonia in a 1:2 ratio at 250–300 °C with a conversion of 50%. An alternative more efficient route begins with sodium borohydride and ammonium sulfate: 6 NaBH4 + 3 (NH4)2SO4 → 2 B3N3H6 + 3 Na2SO4 + 18 H.

Chemical formula: B3H6N3

Boiling point: 53 °C (127 °F; 326 K) (55 °C at 105 Pa)

CAS Number: 6569-51-3

Molar mass: 80.50 g/mol

Answered by shradhakarbari13
0

Answer:

Borazine can be synthesized by treating diborane and ammonia in a 1:2 ratio at 250–300 °C with a conversion of 50%. An alternative more efficient route begins with sodium borohydride and ammonium sulfate: 6 NaBH4 + 3 (NH4)2SO4 → 2 B3N3H6 + 3 Na2SO4 + 18 H.

Chemical formula: B3H6N3

CAS Number: 6569-51-3

Magnetic susceptibility (χ): -49.6·10−6 cm3/mol

Molar mass: 80.50 g/mol.

Hope it will help you

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