Write the product formed when p-nitrochlorobenzene is heated with aqueous naoh at 443k followed by acidification
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Answer: When p-nitrochlorobenzene is heated with aqueous NaOH at 443k then it forms p-nitrophenol with Sodiumhydroxide.
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The product formed when p-nitrochlorobenzene is heated with aqueous NaOH at 443k followed by addition of acid is m-nitrophenol.
- The above reaction is an example of second order nucleophilic aromatic substitution.
- First step is the formation of benzyne as an intermediate by elimination of HCl.
- After that , the hydroxyl group does a nucleophilic addition on the meta position.
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