Question

write the product of zeroes of the quadratic polynomial.
2x² - 5x+3.​

Answer 1

$\\ \\ \huge●Solution:-$

$2x² - 5x+3 = 0 \\ \\ \implies {2}x^{2} - (3 + 2)x + 3 = 0 \\ \\ \implies 2 {x}^{2} - 3x - 2x + 3 = 0\\ \\ \implies \: x(2x - 3) - 1(2x - 3) = 0$

$\\ \\ \implies \: (2x - 3)(x - 1) = 0 \\ \\ \because(2x - 3) = 0 \\ 2x = 3 \\ x = \frac{3}{2} \\ \\ or. \: \: \: \because(x - 1) = 0 \\ x = 1$

Answer 2

●Solution:−

\begin{gathered}2x² - 5x+3 = 0 \\ \\ \implies {2}x^{2} - (3 + 2)x + 3 = 0 \\ \\ \implies 2 {x}^{2} - 3x - 2x + 3 = 0\\ \\ \implies \: x(2x - 3) - 1(2x - 3) = 0 \\ \\ \end{gathered}

2x²−5x+3=0

⟹2x

2

−(3+2)x+3=0

⟹2x

2

−3x−2x+3=0

⟹x(2x−3)−1(2x−3)=0

\begin{gathered} \\ \\ \implies \: (2x - 3)(x - 1) = 0 \\ \\ \because(2x - 3) = 0 \\ 2x = 3 \\ x = \frac{3}{2} \\ \\ or. \: \: \: \because(x - 1) = 0 \\ x = 1 \\ \\ \end{gathered}

⟹(2x−3)(x−1)=0

∵(2x−3)=0

2x=3

x=

2

3

or.∵(x−1)=0

x=1

\begin{gathered} \\ \\ \end{gathered}